Integrand size = 26, antiderivative size = 338 \[ \int \frac {\sqrt {a+b x^2} \left (A+B x^2\right )}{(e x)^{7/2}} \, dx=-\frac {2 (A b+5 a B) \sqrt {a+b x^2}}{5 a e^3 \sqrt {e x}}+\frac {4 \sqrt {b} (A b+5 a B) \sqrt {e x} \sqrt {a+b x^2}}{5 a e^4 \left (\sqrt {a}+\sqrt {b} x\right )}-\frac {2 A \left (a+b x^2\right )^{3/2}}{5 a e (e x)^{5/2}}-\frac {4 \sqrt [4]{b} (A b+5 a B) \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{b} \sqrt {e x}}{\sqrt [4]{a} \sqrt {e}}\right )|\frac {1}{2}\right )}{5 a^{3/4} e^{7/2} \sqrt {a+b x^2}}+\frac {2 \sqrt [4]{b} (A b+5 a B) \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{b} \sqrt {e x}}{\sqrt [4]{a} \sqrt {e}}\right ),\frac {1}{2}\right )}{5 a^{3/4} e^{7/2} \sqrt {a+b x^2}} \]
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Time = 0.19 (sec) , antiderivative size = 338, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {464, 283, 335, 311, 226, 1210} \[ \int \frac {\sqrt {a+b x^2} \left (A+B x^2\right )}{(e x)^{7/2}} \, dx=\frac {2 \sqrt [4]{b} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} (5 a B+A b) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{b} \sqrt {e x}}{\sqrt [4]{a} \sqrt {e}}\right ),\frac {1}{2}\right )}{5 a^{3/4} e^{7/2} \sqrt {a+b x^2}}-\frac {4 \sqrt [4]{b} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} (5 a B+A b) E\left (2 \arctan \left (\frac {\sqrt [4]{b} \sqrt {e x}}{\sqrt [4]{a} \sqrt {e}}\right )|\frac {1}{2}\right )}{5 a^{3/4} e^{7/2} \sqrt {a+b x^2}}+\frac {4 \sqrt {b} \sqrt {e x} \sqrt {a+b x^2} (5 a B+A b)}{5 a e^4 \left (\sqrt {a}+\sqrt {b} x\right )}-\frac {2 \sqrt {a+b x^2} (5 a B+A b)}{5 a e^3 \sqrt {e x}}-\frac {2 A \left (a+b x^2\right )^{3/2}}{5 a e (e x)^{5/2}} \]
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Rule 226
Rule 283
Rule 311
Rule 335
Rule 464
Rule 1210
Rubi steps \begin{align*} \text {integral}& = -\frac {2 A \left (a+b x^2\right )^{3/2}}{5 a e (e x)^{5/2}}+\frac {(A b+5 a B) \int \frac {\sqrt {a+b x^2}}{(e x)^{3/2}} \, dx}{5 a e^2} \\ & = -\frac {2 (A b+5 a B) \sqrt {a+b x^2}}{5 a e^3 \sqrt {e x}}-\frac {2 A \left (a+b x^2\right )^{3/2}}{5 a e (e x)^{5/2}}+\frac {(2 b (A b+5 a B)) \int \frac {\sqrt {e x}}{\sqrt {a+b x^2}} \, dx}{5 a e^4} \\ & = -\frac {2 (A b+5 a B) \sqrt {a+b x^2}}{5 a e^3 \sqrt {e x}}-\frac {2 A \left (a+b x^2\right )^{3/2}}{5 a e (e x)^{5/2}}+\frac {(4 b (A b+5 a B)) \text {Subst}\left (\int \frac {x^2}{\sqrt {a+\frac {b x^4}{e^2}}} \, dx,x,\sqrt {e x}\right )}{5 a e^5} \\ & = -\frac {2 (A b+5 a B) \sqrt {a+b x^2}}{5 a e^3 \sqrt {e x}}-\frac {2 A \left (a+b x^2\right )^{3/2}}{5 a e (e x)^{5/2}}+\frac {\left (4 \sqrt {b} (A b+5 a B)\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a+\frac {b x^4}{e^2}}} \, dx,x,\sqrt {e x}\right )}{5 \sqrt {a} e^4}-\frac {\left (4 \sqrt {b} (A b+5 a B)\right ) \text {Subst}\left (\int \frac {1-\frac {\sqrt {b} x^2}{\sqrt {a} e}}{\sqrt {a+\frac {b x^4}{e^2}}} \, dx,x,\sqrt {e x}\right )}{5 \sqrt {a} e^4} \\ & = -\frac {2 (A b+5 a B) \sqrt {a+b x^2}}{5 a e^3 \sqrt {e x}}+\frac {4 \sqrt {b} (A b+5 a B) \sqrt {e x} \sqrt {a+b x^2}}{5 a e^4 \left (\sqrt {a}+\sqrt {b} x\right )}-\frac {2 A \left (a+b x^2\right )^{3/2}}{5 a e (e x)^{5/2}}-\frac {4 \sqrt [4]{b} (A b+5 a B) \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {e x}}{\sqrt [4]{a} \sqrt {e}}\right )|\frac {1}{2}\right )}{5 a^{3/4} e^{7/2} \sqrt {a+b x^2}}+\frac {2 \sqrt [4]{b} (A b+5 a B) \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {e x}}{\sqrt [4]{a} \sqrt {e}}\right )|\frac {1}{2}\right )}{5 a^{3/4} e^{7/2} \sqrt {a+b x^2}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.04 (sec) , antiderivative size = 95, normalized size of antiderivative = 0.28 \[ \int \frac {\sqrt {a+b x^2} \left (A+B x^2\right )}{(e x)^{7/2}} \, dx=-\frac {2 x \sqrt {a+b x^2} \left (A \left (a+b x^2\right ) \sqrt {1+\frac {b x^2}{a}}+(A b+5 a B) x^2 \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},-\frac {1}{4},\frac {3}{4},-\frac {b x^2}{a}\right )\right )}{5 a (e x)^{7/2} \sqrt {1+\frac {b x^2}{a}}} \]
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Time = 3.07 (sec) , antiderivative size = 242, normalized size of antiderivative = 0.72
method | result | size |
risch | \(-\frac {2 \sqrt {b \,x^{2}+a}\, \left (2 A b \,x^{2}+5 B a \,x^{2}+A a \right )}{5 x^{2} a \,e^{3} \sqrt {e x}}+\frac {2 \left (A b +5 B a \right ) \sqrt {-a b}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, \left (-\frac {2 \sqrt {-a b}\, E\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{b}+\frac {\sqrt {-a b}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{b}\right ) \sqrt {\left (b \,x^{2}+a \right ) e x}}{5 a \sqrt {b e \,x^{3}+a e x}\, e^{3} \sqrt {e x}\, \sqrt {b \,x^{2}+a}}\) | \(242\) |
elliptic | \(\frac {\sqrt {\left (b \,x^{2}+a \right ) e x}\, \left (-\frac {2 A \sqrt {b e \,x^{3}+a e x}}{5 e^{4} x^{3}}-\frac {2 \left (b e \,x^{2}+a e \right ) \left (2 A b +5 B a \right )}{5 e^{4} a \sqrt {x \left (b e \,x^{2}+a e \right )}}+\frac {\left (\frac {B b}{e^{3}}+\frac {b \left (2 A b +5 B a \right )}{5 a \,e^{3}}\right ) \sqrt {-a b}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, \left (-\frac {2 \sqrt {-a b}\, E\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{b}+\frac {\sqrt {-a b}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{b}\right )}{b \sqrt {b e \,x^{3}+a e x}}\right )}{\sqrt {e x}\, \sqrt {b \,x^{2}+a}}\) | \(276\) |
default | \(\frac {\frac {4 A \sqrt {2}\, \sqrt {\frac {b x +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {\frac {-b x +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, E\left (\sqrt {\frac {b x +\sqrt {-a b}}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right ) a b \,x^{2}}{5}-\frac {2 A \sqrt {2}\, \sqrt {\frac {b x +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {\frac {-b x +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, F\left (\sqrt {\frac {b x +\sqrt {-a b}}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right ) a b \,x^{2}}{5}+4 B \sqrt {2}\, \sqrt {\frac {b x +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {\frac {-b x +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, E\left (\sqrt {\frac {b x +\sqrt {-a b}}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right ) a^{2} x^{2}-2 B \sqrt {2}\, \sqrt {\frac {b x +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {\frac {-b x +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, F\left (\sqrt {\frac {b x +\sqrt {-a b}}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right ) a^{2} x^{2}-\frac {4 A \,b^{2} x^{4}}{5}-2 B a b \,x^{4}-\frac {6 a A b \,x^{2}}{5}-2 a^{2} B \,x^{2}-\frac {2 a^{2} A}{5}}{x^{2} \sqrt {b \,x^{2}+a}\, e^{3} \sqrt {e x}\, a}\) | \(417\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.10 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.23 \[ \int \frac {\sqrt {a+b x^2} \left (A+B x^2\right )}{(e x)^{7/2}} \, dx=-\frac {2 \, {\left (2 \, {\left (5 \, B a + A b\right )} \sqrt {b e} x^{3} {\rm weierstrassZeta}\left (-\frac {4 \, a}{b}, 0, {\rm weierstrassPInverse}\left (-\frac {4 \, a}{b}, 0, x\right )\right ) + {\left ({\left (5 \, B a + 2 \, A b\right )} x^{2} + A a\right )} \sqrt {b x^{2} + a} \sqrt {e x}\right )}}{5 \, a e^{4} x^{3}} \]
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Result contains complex when optimal does not.
Time = 12.84 (sec) , antiderivative size = 107, normalized size of antiderivative = 0.32 \[ \int \frac {\sqrt {a+b x^2} \left (A+B x^2\right )}{(e x)^{7/2}} \, dx=\frac {A \sqrt {a} \Gamma \left (- \frac {5}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {5}{4}, - \frac {1}{2} \\ - \frac {1}{4} \end {matrix}\middle | {\frac {b x^{2} e^{i \pi }}{a}} \right )}}{2 e^{\frac {7}{2}} x^{\frac {5}{2}} \Gamma \left (- \frac {1}{4}\right )} + \frac {B \sqrt {a} \Gamma \left (- \frac {1}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, - \frac {1}{4} \\ \frac {3}{4} \end {matrix}\middle | {\frac {b x^{2} e^{i \pi }}{a}} \right )}}{2 e^{\frac {7}{2}} \sqrt {x} \Gamma \left (\frac {3}{4}\right )} \]
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\[ \int \frac {\sqrt {a+b x^2} \left (A+B x^2\right )}{(e x)^{7/2}} \, dx=\int { \frac {{\left (B x^{2} + A\right )} \sqrt {b x^{2} + a}}{\left (e x\right )^{\frac {7}{2}}} \,d x } \]
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\[ \int \frac {\sqrt {a+b x^2} \left (A+B x^2\right )}{(e x)^{7/2}} \, dx=\int { \frac {{\left (B x^{2} + A\right )} \sqrt {b x^{2} + a}}{\left (e x\right )^{\frac {7}{2}}} \,d x } \]
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Timed out. \[ \int \frac {\sqrt {a+b x^2} \left (A+B x^2\right )}{(e x)^{7/2}} \, dx=\int \frac {\left (B\,x^2+A\right )\,\sqrt {b\,x^2+a}}{{\left (e\,x\right )}^{7/2}} \,d x \]
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